x^2(x-4)+2x(x-4)+(x-4)=0

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Solution for x^2(x-4)+2x(x-4)+(x-4)=0 equation: 


Simplifying
x2(x + -4) + 2x(x + -4) + (x + -4) = 0

Reorder the terms:
x2(-4 + x) + 2x(x + -4) + (x + -4) = 0
(-4 * x2 + x * x2) + 2x(x + -4) + (x + -4) = 0
(-4x2 + x3) + 2x(x + -4) + (x + -4) = 0

Reorder the terms:
-4x2 + x3 + 2x(-4 + x) + (x + -4) = 0
-4x2 + x3 + (-4 * 2x + x * 2x) + (x + -4) = 0
-4x2 + x3 + (-8x + 2x2) + (x + -4) = 0

Reorder the terms:
-4x2 + x3 + -8x + 2x2 + (-4 + x) = 0

Remove parenthesis around (-4 + x)
-4x2 + x3 + -8x + 2x2 + -4 + x = 0

Reorder the terms:
-4 + -8x + x + -4x2 + 2x2 + x3 = 0

Combine like terms: -8x + x = -7x
-4 + -7x + -4x2 + 2x2 + x3 = 0

Combine like terms: -4x2 + 2x2 = -2x2
-4 + -7x + -2x2 + x3 = 0

Solving
-4 + -7x + -2x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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